Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
g2(x, y) -> x
g2(x, y) -> y
f3(s1(x), y, y) -> f3(y, x, s1(x))
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
g2(x, y) -> x
g2(x, y) -> y
f3(s1(x), y, y) -> f3(y, x, s1(x))
Q is empty.
Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F3(s1(x), y, y) -> F3(y, x, s1(x))
The TRS R consists of the following rules:
g2(x, y) -> x
g2(x, y) -> y
f3(s1(x), y, y) -> f3(y, x, s1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F3(s1(x), y, y) -> F3(y, x, s1(x))
The TRS R consists of the following rules:
g2(x, y) -> x
g2(x, y) -> y
f3(s1(x), y, y) -> f3(y, x, s1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.